b is the base of the triangle

h is the height of the triangle

Find the area of a triangle with base 6 cm and height 8 cm.

Solution:

A = (1/2)bh

A= (1/2)(6 cm)(8 cm) = 24 cm².

Requested by: Zaib

Find the perimeter of a triangle with sides of length 3 cm, 4 cm, and 5 cm.

Solution:

P = a + b + c

P = 3 cm + 4 cm + 5 cm = 12 cm.

Requested by: Zaib

Find the perimeter of a triangle with sides of length 12 cm, 15 cm, and 18 cm.

Solution:

P = a + b + c =

P = 12 cm + 15 cm + 18 cm = 45 cm.

Requested by: Ameer

Find the area of an equilateral triangle with side length 10 cm.

Solution:

A = (sqrt(3)/4)s²

A = (sqrt(3)/4)(10 cm)² = 25(sqrt(3)) cm².

Requested by: Saroop

Find the perimeter of an isosceles triangle with sides of length 6 cm, 6 cm, and 8 cm.

Solution:

P = a + b + c

P= 6 cm + 6 cm + 8 cm = 20 cm.

Requested by: Naeem

Find the area of an isosceles triangle with base 8 cm and height 6 cm.

Solution:

Area = (1/2) x base x height

Area = (1/2) x 8 cm x 6 cm

Area = 24 cm²

Requested by: Naeem

Find the perimeter of a right triangle with hypotenuse 10 cm and one leg of length 6 cm.

Solution:

Let the other leg of the triangle be x cm.

Using Pythagorean theorem, we have:

x² + 6² = 10²

x² + 36 = 100

x² = 64

x = 8 cm

Therefore, the perimeter of the triangle is:

Perimeter = 6 cm + 8 cm + 10 cm

Perimeter = 24 cm

Requested by: Kantesh

Find the area of a triangle with a base of 10 cm and a height of 6 cm.

Solution:

Area = (1/2)bh = (1/2) * 10 cm * 6 cm = 30 cm^2

Requested by: Ali Raza

Find the area of a triangle with side lengths of 6 cm, 8 cm, and 10 cm.

Solution:

This is a special triangle known as a “right triangle”, since one of its angles measures 90 degrees.

We can use the formula for the area of a triangle and the Pythagorean theorem to find its height:

Area = (1/2)bh

b = 6 cm (the length of the base)

c = 10 cm (the length of the hypotenuse)

a = sqrt(c^2 – b^2) = sqrt(10^2 – 6^2) = 8 cm (the length of the height)

Therefore, the area of the triangle is:

Area = (1/2)bh = (1/2) * 6 cm * 8 cm = 24 cm^2

Requested by: Saramd

Find the perimeter of a triangle with side lengths of 7 cm, 8 cm, and 9 cm.

Solution:

Perimeter = sum of all sides = 7 cm + 8 cm + 9 cm = 24 cm

Requested by: Sarmad

Find the perimeter of an isosceles triangle with base length 6 cm and height 8 cm.

Solution:

Since this is an isosceles triangle, we know that the two other sides are equal.

Let’s call their length x.

Using the Pythagorean theorem, we can find x:

x^2 = 8^2 + (1/2 * 6)^2 = 64 + 9 = 73

x = sqrt(73) ≈ 8.5 cm

The perimeter of the triangle is:

Perimeter = base + 2 equal sides = 6 cm + 2(8.5 cm) = 23 cm.

Requested by: Sarmad

Find the perimeter of a triangle with sides of length 6 cm, 8 cm, and 10 cm.

Solution:

Perimeter = 6 cm + 8 cm + 10 cm

Perimeter = 24 cm

Requested by: Hallar

Find the area of a right triangle with legs of length 3 cm and 4 cm.

Solution:

Area = (1/2) x base x height

Area = (1/2) x 3 cm x 4 cm

Area = 6 cm²

Requested by: Sarmad

Find the perimeter of an equilateral triangle with sides of length 5 cm.

Solution:

Perimeter = 3 x side length

Perimeter = 3 x 5 cm

Perimeter = 15 cm

Requested by: Sarmad

Find the perimeter of a right triangle with legs of length 5 cm and 12 cm.

Solution:

Using Pythagorean theorem, we have:

hypotenuse = sqrt(5² + 12²) = 13 cm

Perimeter = 5 cm + 12 cm + 13 cm

Perimeter = 30 cm

Requested by: Kabeer

Find the area of a triangle with sides of length 3 cm, 4 cm, and 5 cm.

Solution:

This is a right triangle, so we can use the formula for the area of a right triangle:

Area = (1/2) x base x height

Area = (1/2) x 3 cm x 4 cm

Area = 6 cm²

Requested by: Kabeer

Find the perimeter of a triangle with sides of length 12 cm, 16 cm, and 20 cm.

Solution:

Perimeter = 12 cm + 16 cm + 20 cm

Perimeter = 48 cm

Requested by: Faizan

Find the perimeter of a triangle with sides of length 9 cm, 12 cm, and 15 cm.

Solution: P = a + b + c = 9 cm + 12 cm + 15 cm = 36 cm.

Requested by: Faizan

Find the area of an equilateral triangle with side length 8 cm.

Solution: An equilateral triangle has all sides equal, so the height can be found using the Pythagorean theorem:

h = sqrt(8 cm² – (4 cm²)) = sqrt(48) cm = 4sqrt(3) cm.

Therefore, A = (1/2)bh = (1/2)(8 cm)(4sqrt(3) cm)

A = 16sqrt(3) cm².

Requested by: Faizan

Find the area of a right triangle with legs of length 3 cm and 4 cm.

Solution: A = (1/2)bh = (1/2)(3 cm)(4 cm) = 6 cm².

Requested by: Hamid

Find the perimeter of a right triangle with legs of length 5 cm and 12 cm.

Solution:

The hypotenuse can be found using the Pythagorean theorem:

c = sqrt(5 cm² + 12 cm²) = 13 cm.

Therefore, P = a + b + c = 5 cm + 12 cm + 13 cm

P = 30 cm.

Requested by: Hamid

Find the area of a triangle with base 12 cm and height 9 cm.

Solution: A = (1/2)bh = (1/2)(12 cm)(9 cm) = 54 cm².

Requested by: Ali Nawaz

Find the perimeter of a triangle with sides of length 8 cm, 10 cm, and 12 cm.

Solution: P = a + b + c = 8 cm + 10 cm + 12 cm = 30 cm.

Requested by: Ali Nawaz